گۆڕینی گۆڕەک

${\displaystyle x^{6}-9x^{3}+8=0.\,}$ 

${\displaystyle (x^{3})^{2}-9(x^{3})+8=0}$ 

x = ${\displaystyle {\sqrt[{3}]{u}}}$ 

${\displaystyle u^{2}-9u+8=0,}$ 

${\displaystyle u=1\quad {\text{و}}\quad u=8.}$ 

${\displaystyle x^{3}=1\quad {\text{and}}\quad x^{3}=8.}$ 

${\displaystyle x=(1)^{1/3}=1\quad {\text{و}}\quad x=(8)^{1/3}=2.}$