ڕێسای لۆپیتاڵ

${\displaystyle \lim _{x\to c}f(x)=\lim _{x\to c}g(x)=0\ }$ 

${\displaystyle \lim _{x\to c}f(x)=\lim _{x\to c}g(x)=\pm \infty }$ 

${\displaystyle \lim _{x\to c}{\frac {f(x)}{g(x)}}=\lim _{x\to c}{\frac {f'(x)}{g'(x)}}}$ 

${\displaystyle {\begin{aligned}\lim _{x\to 0}{\frac {\sin x}{x}}&=\lim _{x\to 0}{\frac {\cos x}{1}}\\&=1\end{aligned}}}$