Q値

${\displaystyle Q={\frac {\omega _{0}}{\omega _{2}-\omega _{1}}}}$

${\displaystyle Q={\frac {1}{R}}{\sqrt {\frac {L}{C}}}}$ 

${\displaystyle \omega ={\sqrt {\frac {1}{LC}}}}$ 

${\displaystyle Q={\frac {\omega {}L}{R}}={\frac {1}{\omega {}CR}}}$ 

${\displaystyle Q={R}{\sqrt {\frac {C}{L}}}}$ 

${\displaystyle Q={\frac {\sqrt {MK}}{R}}}$ 

${\displaystyle \omega ={\sqrt {\frac {K}{M}}}}$ 

${\displaystyle Q={\frac {\omega {}M}{R}}}$ 

${\displaystyle Q={\frac {1}{2\zeta }}={\frac {1}{\eta }}}$ 

${\displaystyle {d^{2}x \over dt^{2}}+2\zeta \omega _{n}{dx \over dt}+\omega _{n}x=-{F_{0} \over k}\omega _{n}^{2}\cos \omega t}$ 

${\displaystyle x=A\cos \omega t+B\sin \omega t}$ 

${\displaystyle x={F_{0} \over k}{1 \over {\left\{{1-\left({\omega \over \omega _{n}}\right)^{2}}\right\}^{2}+\left({2\zeta {\omega \over \omega _{n}}}\right)^{2}}}\left[\left\{{1-\left({\omega \over \omega _{n}}\right)^{2}}\right\}\cos \omega t+2\zeta {\omega \over \omega _{n}}\sin \omega t\right]}$ 

${\displaystyle x(\omega _{n})={F_{0} \over k}{1 \over {2\zeta }}\sin \omega t}$ 

${\displaystyle x(\omega _{n})={F_{0} \over k}Q\sin \omega t}$ 

${\displaystyle x_{0}={F_{0} \over k}}$ 

${\displaystyle {x(\omega _{n}) \over x_{0}}=Q}$ 

${\displaystyle Q={\frac {2\pi \nu {\mathcal {E}}}{P}}}$