Zarankiewicz Problem

The Zarankiewicz problem, an unsolved problem in mathematics, asks for the largest possible number of edges in a bipartite graph that has a given number of vertices and has no complete bipartite subgraphs of a given size.

It belongs to the field of extremal graph theory, a branch of combinatorics, and is named after the Polish mathematician Kazimierz Zarankiewicz, who proposed several special cases of the problem in 1951.

Problem statement

A bipartite graph Zarankiewicz Problem  consists of two disjoint sets of vertices Zarankiewicz Problem  and Zarankiewicz Problem , and a set of edges each of which connects a vertex in Zarankiewicz Problem  to a vertex in Zarankiewicz Problem . No two edges can both connect the same pair of vertices. A complete bipartite graph is a bipartite graph in which every pair of a vertex from Zarankiewicz Problem  and a vertex from Zarankiewicz Problem  is connected to each other. A complete bipartite graph in which Zarankiewicz Problem  has Zarankiewicz Problem  vertices and Zarankiewicz Problem  has Zarankiewicz Problem  vertices is denoted Zarankiewicz Problem . If Zarankiewicz Problem  is a bipartite graph, and there exists a set of Zarankiewicz Problem  vertices of Zarankiewicz Problem  and Zarankiewicz Problem  vertices of Zarankiewicz Problem  that are all connected to each other, then these vertices induce a subgraph of the form Zarankiewicz Problem . (In this formulation, the ordering of Zarankiewicz Problem  and Zarankiewicz Problem  is significant: the set of Zarankiewicz Problem  vertices must be from Zarankiewicz Problem  and the set of Zarankiewicz Problem  vertices must be from Zarankiewicz Problem , not vice versa.)

The Zarankiewicz function Zarankiewicz Problem  denotes the maximum possible number of edges in a bipartite graph Zarankiewicz Problem  for which Zarankiewicz Problem  and Zarankiewicz Problem , but which does not contain a subgraph of the form Zarankiewicz Problem . As a shorthand for an important special case, Zarankiewicz Problem  is the same as Zarankiewicz Problem . The Zarankiewicz problem asks for a formula for the Zarankiewicz function, or (failing that) for tight asymptotic bounds on the growth rate of Zarankiewicz Problem  assuming that Zarankiewicz Problem  is a fixed constant, in the limit as Zarankiewicz Problem  goes to infinity.

For Zarankiewicz Problem  this problem is the same as determining cages with girth six. The Zarankiewicz problem, cages and finite geometry are strongly interrelated.

The same problem can also be formulated in terms of digital geometry. The possible edges of a bipartite graph Zarankiewicz Problem  can be visualized as the points of a Zarankiewicz Problem  rectangle in the integer lattice, and a complete subgraph is a set of rows and columns in this rectangle in which all points are present. Thus, Zarankiewicz Problem  denotes the maximum number of points that can be placed within an Zarankiewicz Problem  grid in such a way that no subset of rows and columns forms a complete Zarankiewicz Problem  grid. An alternative and equivalent definition is that Zarankiewicz Problem  is the smallest integer Zarankiewicz Problem  such that every (0,1)-matrix of size Zarankiewicz Problem  with Zarankiewicz Problem  ones must have a set of Zarankiewicz Problem  rows and Zarankiewicz Problem  columns such that the corresponding Zarankiewicz Problem  submatrix is made up only of 1s.

Examples

Zarankiewicz Problem 
A bipartite graph with 4 vertices on each side, 13 edges, and no Zarankiewicz Problem  subgraph, and an equivalent set of 13 points in a 4 × 4 grid, showing that Zarankiewicz Problem .

The number Zarankiewicz Problem  asks for the maximum number of edges in a bipartite graph with Zarankiewicz Problem  vertices on each side that has no 4-cycle (its girth is six or more). Thus, Zarankiewicz Problem  (achieved by a three-edge path), and Zarankiewicz Problem  (a hexagon).

In his original formulation of the problem, Zarankiewicz asked for the values of Zarankiewicz Problem  for Zarankiewicz Problem . The answers were supplied soon afterwards by Wacław Sierpiński: Zarankiewicz Problem , Zarankiewicz Problem , and Zarankiewicz Problem . The case of Zarankiewicz Problem  is relatively simple: a 13-edge bipartite graph with four vertices on each side of the bipartition, and no Zarankiewicz Problem  subgraph, may be obtained by adding one of the long diagonals to the graph of a cube. In the other direction, if a bipartite graph with 14 edges has four vertices on each side, then two vertices on each side must have degree four. Removing these four vertices and their 12 incident edges leaves a nonempty set of edges, any of which together with the four removed vertices forms a Zarankiewicz Problem  subgraph.

Upper bounds

The Kővári–Sós–Turán theorem provides an upper bound on the solution to the Zarankiewicz problem. It was established by Tamás Kővári, Vera T. Sós and Pál Turán shortly after the problem had been posed:

    Zarankiewicz Problem 

Kővári, Sós, and Turán originally proved this inequality for Zarankiewicz Problem . Shortly afterwards, Hyltén-Cavallius observed that essentially the same argument can be used to prove the above inequality. An improvement on the second term of the upper bound on Zarankiewicz Problem  was given by Štefan Znám:

    Zarankiewicz Problem 

If Zarankiewicz Problem  and Zarankiewicz Problem  are assumed to be constant, then asymptotically, using the big O notation, these formulae can be expressed as

    Zarankiewicz Problem ;
    Zarankiewicz Problem .

In the particular case Zarankiewicz Problem , assuming without loss of generality that Zarankiewicz Problem , we have the asymptotic upper bound

    Zarankiewicz Problem 

Lower bounds

One can verify that among the two asymptotic upper bounds of Zarankiewicz Problem  in the previous section, the first bound is better when Zarankiewicz Problem , and the second bound becomes better when Zarankiewicz Problem . Therefore, if one can show a lower bound for Zarankiewicz Problem  that matches the upper bound up to a constant, then by a simple sampling argument (on either an Zarankiewicz Problem  bipartite graph or an Zarankiewicz Problem  bipartite graph that achieves the maximum edge number), we can show that for all Zarankiewicz Problem , one of the above two upper bounds is tight up to a constant. This leads to the following question: is it the case that for any fixed Zarankiewicz Problem  and Zarankiewicz Problem , we have

    Zarankiewicz Problem ?

In the special case Zarankiewicz Problem , up to constant factors, Zarankiewicz Problem  has the same order as Zarankiewicz Problem , the maximum number of edges in an Zarankiewicz Problem -vertex (not necessarily bipartite) graph that has no Zarankiewicz Problem  as a subgraph. In one direction, a bipartite graph with Zarankiewicz Problem  vertices on each side and Zarankiewicz Problem  edges must have a subgraph with Zarankiewicz Problem  vertices and at least Zarankiewicz Problem  edges; this can be seen from choosing Zarankiewicz Problem  vertices uniformly at random from each side, and taking the expectation. In the other direction, we can transform a graph with Zarankiewicz Problem  vertices and no copy of Zarankiewicz Problem  into a bipartite graph with Zarankiewicz Problem  vertices on each side of its bipartition, twice as many edges and still no copy of Zarankiewicz Problem , by taking its bipartite double cover. Same as above, with the convention that Zarankiewicz Problem , it has been conjectured that

    Zarankiewicz Problem 

for all constant values of Zarankiewicz Problem .

For some specific values of Zarankiewicz Problem  (e.g., for Zarankiewicz Problem  sufficiently larger than Zarankiewicz Problem , or for Zarankiewicz Problem ), the above statements have been proved using various algebraic and random algebraic constructions. At the same time, the answer to the general question is still unknown to us.

Incidence graphs in finite geometry

Zarankiewicz Problem 
The Levi graph of the Fano plane gives rise to the Heawood graph, a bipartite graph with seven vertices on each side, 21 edges, and no 4-cycles.

For Zarankiewicz Problem , a bipartite graph with Zarankiewicz Problem  vertices on each side, Zarankiewicz Problem  edges, and no Zarankiewicz Problem  may be obtained as the Levi graph, or point-line incidence graph, of a projective plane of order Zarankiewicz Problem , a system of Zarankiewicz Problem  points and Zarankiewicz Problem  lines in which each two points determine a unique line, and each two lines intersect at a unique point. We construct a bipartite graph associated to this projective plane that has one vertex part as its points, the other vertex part as its lines, such that a point and a line is connected if and only if they are incident in the projective plane. This leads to a Zarankiewicz Problem -free graph with Zarankiewicz Problem  vertices and Zarankiewicz Problem  edges. Since this lower bound matches the upper bound given by I. Reiman, we have the asymptotic

    Zarankiewicz Problem 

For Zarankiewicz Problem , bipartite graphs with Zarankiewicz Problem  vertices on each side, Zarankiewicz Problem  edges, and no Zarankiewicz Problem  may again be constructed from finite geometry, by letting the vertices represent points and spheres (of a carefully chosen fixed radius) in a three-dimensional finite affine space, and letting the edges represent point-sphere incidences.

More generally, consider Zarankiewicz Problem  and any Zarankiewicz Problem . Let Zarankiewicz Problem  be the Zarankiewicz Problem -element finite field, and Zarankiewicz Problem  be an element of multiplicative order Zarankiewicz Problem , in the sense that Zarankiewicz Problem  form a Zarankiewicz Problem -element subgroup of the multiplicative group Zarankiewicz Problem . We say that two nonzero elements Zarankiewicz Problem  are equivalent if we have Zarankiewicz Problem  and Zarankiewicz Problem  for some Zarankiewicz Problem . Consider a graph Zarankiewicz Problem  on the set of all equivalence classes Zarankiewicz Problem , such that Zarankiewicz Problem  and Zarankiewicz Problem  are connected if and only if Zarankiewicz Problem . One can verify that Zarankiewicz Problem  is well-defined and free of Zarankiewicz Problem , and every vertex in Zarankiewicz Problem  has degree Zarankiewicz Problem  or Zarankiewicz Problem . Hence we have the upper bound

    Zarankiewicz Problem 

Norm graphs and projective norm graphs

For Zarankiewicz Problem  sufficiently larger than Zarankiewicz Problem , the above conjecture Zarankiewicz Problem  was verified by Kollár, Rónyai, and Szabó and Alon, Rónyai, and Szabó using the construction of norm graphs and projective norm graphs over finite fields.

For Zarankiewicz Problem , consider the norm graph NormGraphp,s with vertex set Zarankiewicz Problem , such that every two vertices Zarankiewicz Problem  are connected if and only if Zarankiewicz Problem , where Zarankiewicz Problem  is the norm map

    Zarankiewicz Problem 

It is not hard to verify that the graph has Zarankiewicz Problem  vertices and at least Zarankiewicz Problem  edges. To see that this graph is Zarankiewicz Problem -free, observe that any common neighbor Zarankiewicz Problem  of Zarankiewicz Problem  vertices Zarankiewicz Problem  must satisfy

    Zarankiewicz Problem 

for all Zarankiewicz Problem , which a system of equations that has at most Zarankiewicz Problem  solutions.

The same result can be proved for all Zarankiewicz Problem  using the projective norm graph, a construction slightly stronger than the above. The projective norm graph ProjNormGraphp,s is the graph on vertex set Zarankiewicz Problem , such that two vertices Zarankiewicz Problem  are adjacent if and only if Zarankiewicz Problem , where Zarankiewicz Problem  is the norm map defined by Zarankiewicz Problem . By a similar argument to the above, one can verify that it is a Zarankiewicz Problem  -free graph with Zarankiewicz Problem  edges.

The above norm graph approach also gives tight lower bounds on Zarankiewicz Problem  for certain choices of Zarankiewicz Problem . In particular, for Zarankiewicz Problem , Zarankiewicz Problem , and Zarankiewicz Problem , we have

    Zarankiewicz Problem 

In the case Zarankiewicz Problem , consider the bipartite graph Zarankiewicz Problem  with bipartition Zarankiewicz Problem , such that Zarankiewicz Problem  and Zarankiewicz Problem . For Zarankiewicz Problem  and Zarankiewicz Problem , let Zarankiewicz Problem  in Zarankiewicz Problem  if and only if Zarankiewicz Problem , where Zarankiewicz Problem  is the norm map defined above. To see that Zarankiewicz Problem  is Zarankiewicz Problem  -free, consider Zarankiewicz Problem  tuples Zarankiewicz Problem . Observe that if the Zarankiewicz Problem  tuples have a common neighbor, then the Zarankiewicz Problem  must be distinct. Using the same upper bound on he number of solutions to the system of equations, we know that these Zarankiewicz Problem  tuples have at most Zarankiewicz Problem  common neighbors.

Clique partitions

Using a related result on clique partition numbers, Alon, Mellinger, Mubayi and Verstraëte proved a tight lower bound on Zarankiewicz Problem  for arbitrary Zarankiewicz Problem : if Zarankiewicz Problem , then we have

    Zarankiewicz Problem .

For Zarankiewicz Problem , we say that a collection of subsets Zarankiewicz Problem  is a clique partition of Zarankiewicz Problem  if Zarankiewicz Problem  form a partition of Zarankiewicz Problem . Observe that for any Zarankiewicz Problem , if there exists some Zarankiewicz Problem  of size Zarankiewicz Problem  and Zarankiewicz Problem , such that there is a partition of Zarankiewicz Problem  into Zarankiewicz Problem  cliques of size Zarankiewicz Problem , then we have Zarankiewicz Problem . Indeed, supposing Zarankiewicz Problem  is a partition of Zarankiewicz Problem  into Zarankiewicz Problem  cliques of size Zarankiewicz Problem , we can let Zarankiewicz Problem  be the Zarankiewicz Problem  bipartite graph with Zarankiewicz Problem  and Zarankiewicz Problem , such that Zarankiewicz Problem  in Zarankiewicz Problem  if and only if Zarankiewicz Problem . Since the Zarankiewicz Problem  form a clique partition, Zarankiewicz Problem  cannot contain a copy of Zarankiewicz Problem .

It remains to show that such a clique partition exists for any Zarankiewicz Problem . To show this, let Zarankiewicz Problem  be the finite field of size Zarankiewicz Problem  and Zarankiewicz Problem . For every polynomial Zarankiewicz Problem  of degree at most Zarankiewicz Problem  over Zarankiewicz Problem , define Zarankiewicz Problem . Let Zarankiewicz Problem  be the collection of all Zarankiewicz Problem , so that Zarankiewicz Problem  and every Zarankiewicz Problem  has size Zarankiewicz Problem . Clearly no two members of Zarankiewicz Problem  can share Zarankiewicz Problem  members. Since the only Zarankiewicz Problem -sets in Zarankiewicz Problem  that do not belong to Zarankiewicz Problem  are those that have at least two points sharing the same first coordinate, we know that almost all Zarankiewicz Problem -subsets of Zarankiewicz Problem  are contained in some Zarankiewicz Problem .

Randomized algebraic constructions

Alternative proofs of Zarankiewicz Problem  for Zarankiewicz Problem  sufficiently larger than Zarankiewicz Problem  were also given by Blagojević, Bukh and Karasev and by Bukh using the method of random algebraic constructions. The basic idea is to take a random polynomial Zarankiewicz Problem  and consider the graph Zarankiewicz Problem  between two copies of Zarankiewicz Problem  whose edges are all those pairs Zarankiewicz Problem  such that Zarankiewicz Problem .

To start with, let Zarankiewicz Problem  be a prime power and Zarankiewicz Problem . Let

    Zarankiewicz Problem 

be a random polynomial with degree at most Zarankiewicz Problem  in Zarankiewicz Problem , degree at most Zarankiewicz Problem  in Zarankiewicz Problem , and furthermore satisfying Zarankiewicz Problem  for all Zarankiewicz Problem . Let Zarankiewicz Problem  be the associated random graph on vertex set Zarankiewicz Problem , such that two vertices Zarankiewicz Problem  and Zarankiewicz Problem  are adjacent if and only if Zarankiewicz Problem .

To prove the asymptotic lower bound, it suffices to show that the expected number of edges in Zarankiewicz Problem  is Zarankiewicz Problem . For every Zarankiewicz Problem -subset Zarankiewicz Problem , we let Zarankiewicz Problem  denote the vertex subset of Zarankiewicz Problem  that "vanishes on Zarankiewicz Problem ":

    Zarankiewicz Problem .

Using the Lang-Weil bound for polynomials Zarankiewicz Problem  in Zarankiewicz Problem , we can deduce that one always has Zarankiewicz Problem  or Zarankiewicz Problem  for some large constant Zarankiewicz Problem , which implies

    Zarankiewicz Problem .

Since Zarankiewicz Problem  is chosen randomly over Zarankiewicz Problem , it is not hard to show that the right-hand side probability is small, so the expected number of Zarankiewicz Problem -subsets Zarankiewicz Problem  with Zarankiewicz Problem  also turned out to be small. If we remove a vertex from every such Zarankiewicz Problem , then the resulting graph is Zarankiewicz Problem  free, and the expected number of remaining edges is still large. This finishes the proof that Zarankiewicz Problem  for all Zarankiewicz Problem  sufficiently large with respect to Zarankiewicz Problem . More recently, there have been a number of results verifying the conjecture Zarankiewicz Problem  for different values of Zarankiewicz Problem , using similar ideas but with more tools from algebraic geometry.

Applications

The Kővári–Sós–Turán theorem has been used in discrete geometry to bound the number of incidences between geometric objects of various types. As a simple example, a set of Zarankiewicz Problem  points and Zarankiewicz Problem  lines in the Euclidean plane necessarily has no Zarankiewicz Problem , so by the Kővári–Sós–Turán it has Zarankiewicz Problem  point-line incidences. This bound is tight when Zarankiewicz Problem  is much larger than Zarankiewicz Problem , but not when Zarankiewicz Problem  and Zarankiewicz Problem  are nearly equal, in which case the Szemerédi–Trotter theorem provides a tighter Zarankiewicz Problem  bound. However, the Szemerédi–Trotter theorem may be proven by dividing the points and lines into subsets for which the Kővári–Sós–Turán bound is tight.

See also

References

Tags:

Zarankiewicz Problem Problem statementZarankiewicz Problem ExamplesZarankiewicz Problem Upper boundsZarankiewicz Problem Lower boundsZarankiewicz Problem ApplicationsZarankiewicz ProblemBipartite graphCombinatoricsComplete bipartite graphExtremal graph theoryKazimierz Zarankiewicz

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