Maria Isabel de Alcântara Bourbon (28 February 1830 – 5 September 1896) was the third daughter (fifth child) of emperor Pedro I of Brazil and his mistress, Domitila de Castro, Marchioness of Santos.
Maria Isabel de Alcântara | |
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Countess of Iguaçu | |
Full name | Maria Isabel de Alcântara Bourbon |
Born | São Paulo, Empire of Brazil | 28 February 1830
Died | 6 September 1896 São Paulo, São Paulo, Brazil | (aged 66)
Buried | Consolação Cemetery |
Spouse(s) | Pedro Caldeira Brant, Count of Iguaçu (m. 1848; died 1881) |
Issue | 7 |
Father | Pedro I of Brazil |
Mother | Domitila de Castro |
Maria Isabel received the same name as her second sister, the Duchess of Ceará, who died in 1828 at only two months old. She was never given any titles by her father due to his marriage to Amélie of Leuchtenberg. Still, Pedro I acknowledged her as his daughter in his will but gave her no share of his state, except asking for his widow to aid in her education and upbringing. He had wished that she be given a good European education like her oldest sister, the Duchess of Goiás. However, the Marchioness declined to send the girl to Europe.
On 2 September 1848, at the age of eighteen, Maria Isabel married Pedro Caldeira Brant, the Count of Iguaçu, son of Felisberto Caldeira Brant, Marquis of Barbacena. At their wedding, Maria Isabel became the second Countess of Iguaçu. The couple had seven children:
She died on 5 September 1896, at sixty-six years of age, in São Paulo.
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