Phi

Muavrit : (cosϕ+isinϕ)n=cosnϕ+isinnϕ{\displaystyle (cos\phi +isin\phi )^{n}=cos{n\phi }+isin{n\phi }} Rrënjëzimi i numrave kompleks Zgjidhja trigonometike...

}-A_{\phi }{\ddot {\phi }}-2{\dot {A}}_{\phi }{\dot {\phi }}-A_{\rho }{\dot {\phi }}^{2}\right)+{\boldsymbol {\hat {\phi }}}\left({\ddot {A}}_{\phi }+A_{\rho...

\phi } , ϕ E {\displaystyle \phi _{\mathrm {E} }} ose V) lidhet ngushtë me energjine e mundshme, pra: U E = q ϕ {\displaystyle U_{\mathrm {E} }=q\phi }...

={\frac {d}{dt}}\int \Phi ^{*}A\Phi ~dx^{3}=\int \left({\frac {\partial \Phi ^{*}}{\partial t}}\right)A\Phi ~dx^{3}+\int \Phi ^{*}\left({\frac {\partial...

ϕ{\displaystyle \phi } (dSϕdϕ)2+2mUϕ(ϕ)=Γϕ{\displaystyle \left({\frac {dS_{\phi }}{d\phi }}\right)^{2}+2mU_{\phi }(\phi )=\Gamma _{\phi }} ku Γϕ{\displaystyle...

{\bigg (}c_{1}\langle \phi _{1}|+c_{2}\langle \phi _{2}|{\bigg )}\;|\psi \rangle =c_{1}\langle \phi _{1}|\psi \rangle +c_{2}\langle \phi _{2}|\psi \rangle...

\phi )=(2\cos \phi ,2\sin \phi ,1)\,} X ( 3 π / 2 , ϕ ) = ( 2 cos ⁡ ϕ , 2 sin ⁡ ϕ , − 1 ) {\displaystyle X({3\pi /2},\phi )=(2\cos \phi ,2\sin \phi ,-1)\...

{\dot {\phi }}^{2}+mgr\sin \theta =0} and d d t ( m r 2 sin 2 ⁡ θ ϕ ˙ ) = 0 {\displaystyle {\frac {d}{dt}}\left(mr^{2}\sin ^{2}\theta \,{\dot {\phi }}\right)=0}...

Fluksi magnetik, zakonisht shënohet me shkronjën e alfabetit grek Φ (phi), tregon sasinë e intensitetit të fushës magnetike që kalon përmes një sipërfaqeje...

{\begin{aligned}|V|e^{j(\omega t+\phi _{V})}&=|I|e^{j(\omega t+\phi _{I})}|Z|e^{j\theta }\\&=|I||Z|e^{j(\omega t+\phi _{I}+\theta )}\end{aligned}}} Duke...

, {\displaystyle f(\phi ,\psi )\propto \exp[\kappa _{1}\cos(\phi -\mu )+\kappa _{2}\cos(\psi -\nu )+(\cos(\phi -\mu ),\sin(\phi -\mu ))\mathbf {A} (\cos(\psi...

(\phi )&=\operatorname {Rot} (\theta +\phi ),\\[4pt]\operatorname {Ref} (\theta )\,\operatorname {Ref} (\phi )&=\operatorname {Rot} (2\theta -2\phi )...

ϕ{\displaystyle \phi }, një skalar i quajtur densiteti i Lagranzhit L(ϕ,∂ϕ,∂∂ϕ,...,x){\displaystyle {\mathcal {L}}(\phi ,\partial \phi ,\partial \partial \phi ,.....

μ{\displaystyle \mu } që kalonë nëpër pikën M me këndin ϕ{\displaystyle \phi } (lexo:fi) apo më tutje pozia e pikës M në planin meridian μ{\displaystyle...

(}N+h{\big )}\cos {\phi }\cos {\lambda }\\Y&={\big (}N+h{\big )}\cos {\phi }\sin {\lambda }\\Z&=\left({\frac {b^{2}}{a^{2}}}N+h\right)\sin {\phi }\end{aligned}}}...

{d}{dt}}\Phi (\mathbf {r} (t))dt=\Phi (\mathbf {r} (b))-\Phi (\mathbf {r} (a))=\Phi \left(\mathbf {x} _{B}\right)-\Phi \left(\mathbf {x} _{A}\right).\end{aligned}}}...

shpejtësinë e rrotullimit, pra: U≈E=kEϕn=Kn{\displaystyle U\approx E=k_{E}\phi n=Kn} Tahogjeneratori i rrymës së vazhduar përbëhet prej: Statorit me magnet...

elektrik mbi një sipërfaqe S jepet nga: Φ E = ∫ S E ⋅ d A {\displaystyle \Phi _{E}=\int _{S}\mathbf {E} \cdot d\mathbf {A} } ,ku E është intensiteti i...

^{2}\phi }{\partial t^{2}}}+u{\frac {\partial }{\partial x}}\left[S_{\phi }-{\frac {\partial (u\phi )}{\partial x}}\right]={\frac {\partial ^{2}\phi }{\partial...

i f ( i ) ( t ) = ϕ ( t ) {\displaystyle \sum _{i=0}^{n}a_{i}f^{(i)}(t)=\phi (t)} me kushte fillestare të dhëna f ( i ) ( 0 ) = c i {\displaystyle f^{(i)}(0)=c_{i}}...